Hooolaquetal!
El pin 1 y 3 del XLR a masa. y el pin 2 señal. Importante poner el 3 a masa, o mejor aún:
Tip - pin 2
Ring- pin 3
SL- pin 1
Así será un cable balanceado, y cuando lo conectes a un jack sin balancear, éste pondrá el Ring a masa, junto con el SL.
Saludos.
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* - Necesitaras este Puente entre el pin 3 y 1 si la salida balanceada es con transformador. Puede causar problemas con salidas sin transformador
si, pero lo que esta diciendo ahi, es que es recomendable para salidas sin transformador dejar libre el pin3, esto es, pin2 (+) a la punta (T) y el pin1 al anillo y masa (R-S) o en caso de que sea Jack mono a (S).
vamos en definitiva, no conectar el pin3.
Donde dice eso? algun link? habra un porque, no?
Devices with impedance-balanced outputs actively drive the hot output only. The cold output is tied to ground via a resistor that matches (or balances) the output impedance of the hot signal conductor. In other words, there is no audio signal on the cold conductor, but, in a full balanced system, common-mode rejection will be maintained since the impedance is balanced between the two conductors.
Impedance-balanced outputs can connect to unbalanced loads with the cold output 'floated' (unconnected) or connected to ground. There will be no performance or other differences between a floated or grounded cold conductor (pin-3) with impedance-balanced outputs. Using an XLR connector, this corresponds to pin-3 floating or tied to pin-1. The hot signal conductor will be connected to pin-2, as usual, and it will carry the audio information. The shield conductor will be connected, as usual, to pin-1.
Devices with transformer-balanced outputs actively drive the primary winding of the output transformer. The secondary winding of the output transformer delivers a symmetrical signal to the hot and cold signal conductors.
Transformer-balanced outputs must have the cold output tied to the shield conductor when connecting to an unbalanced load. Using an XLR connector, this corresponds to tying pin-3 to pin-1. The hot signal conductor will be connected to pin-2, as usual, and it will carry the audio information. The shield conductor will be connected, as usual, to pin-1.
Devices with active-balanced outputs actively drive both the hot output and the cold output. The signal on the cold output is an inverted (polarity-reversed) version of the signal on the hot output. This creates symmetrical signals between the hot and cold outputs. This is the topology of all Benchmark equipment.
When connecting an active-balanced output to an unbalanced load, it is necessary to leave the cold output (pin-3) floating. Using an XLR connector, pin-3 should not be connected to anything. If a cable is used with pin-3 tied to pin-1 (shield), the output amplifier could be damaged. This type of connection establishes a low/no impedance path to ground. This means the amplifier will drain current, unimpeded, into ground, which is stressful to the output amplifier.
El LA610 si no me equivoco tiene la salida y entrada con trafo, por lo que necesariamente deberia ir con el pin3 (-) unido a la malla.
El joemeek no he conseguido averiguar que tipo de salida balanceada tiene, pero en el manual pone que si se va a conectar a una entrada desbalanceada hay que puentear el pin3. Asi que deduzco que no es activa.
El dav creo que tiene salida activa por lo que deberia llevar desconectado el pin3.
Asi que optare por conectar con un cable XLR/TRS el UA y el Joemeek a la entrada no balanceada, ya que a efectos practicos es como si conectara un cable XLR/TS (con el pin3 puenteado) por el tipo de entrada.
un saludo.
